7^2x+1-2(7^x+1)+7=0

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Solution for 7^2x+1-2(7^x+1)+7=0 equation: 



7^2x+1-2(7^x+1)+7=0

We add all the numbers together, and all the variables

7^2x-2(7^x+1)+8=0

We multiply parentheses

7^2x-14x-2+8=0

We add all the numbers together, and all the variables

-14x+7^2x+6=0

We move all terms containing x to the left, all other terms to the right

-14x+7^2x=-6

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